{"id":1759,"date":"2012-01-07T19:16:08","date_gmt":"2012-01-07T11:16:08","guid":{"rendered":"http:\/\/wamath.sinaapp.com\/?p=1759"},"modified":"2012-01-07T19:16:08","modified_gmt":"2012-01-07T11:16:08","slug":"introduction-of-latex-to-html-plugin","status":"publish","type":"post","link":"https:\/\/lttt.vanabel.cn\/?p=1759","title":{"rendered":"Introduction of LaTeX2HTML Plugin"},"content":{"rendered":"<p>\\title{Introduction to LaTeX2HTML Plugin}<br \/>\n\\author{van abel}<br \/>\n\\email{van141.abel@gmail.com}<br \/>\n\\address{Southwest University}<br \/>\n\\date{\\today}<br \/>\n\\keywords{Latex, Html}<\/p>\n<div style=\"color: #369; text-align: center;\">Please notice that, this is the old user&#8217;s manual of LaTeX2HTML with version less than <code>1.2.3<\/code>, the new manual is <a href=\"https:\/\/lttt.blog.ustc.edu.cn\/the-users-manual-of-latex2html-2-0-0\/\" target=\"_blank\">The User\u2019s Manual of LaTeX2HTML 2.0.0<\/a>.<\/div>\n<p>\\begin{abstract}<br \/>\nThis is an introduction to write your blog using LaTeX language with the help of <em>latex2html<\/em> plugin. Before you testing it, please assure you have installed some plugin of MathJax, the <em>simple-mathjax<\/em> is recommend. The designing principle is to make you publish a post from your latex document more quickly and conveniently. With a litter pre-definition in your latex document, I find it works lovely.<br \/>\n\\end{abstract}<br \/>\n\\tableofcontents<br \/>\n<!--more--><\/p>\n<pre lang=\"latex\">\\title{Introduction to LaTeX to HTML Plugin}\n\\author{van abel}\n\\title{Introduction to LaTeX to HTML Plugin}\n\\author{van abel}\n\\email{van141.abel@gmail.com}\n\\address{Southwest University}\n\\date{\\today}\n\\keywords{Latex, Html}\n\\begin{abstract}\nThis is a introduction to write your blog use LaTeX language the help of \\emph{latex2html} plugin. Before  you test of it, please assure you have installed some plugin of mathjax, the \\emph{simple-mathjax} is recommend. The of design principle is to make you publish a post from your latex document more quickly and convenient. With a litter pre-definition in you latex document, I find it works lovely.\n\\end{abstract}\n\\tableofcontents\n<\/pre>\n<p>\\section{One Words Before the Starting}<br \/>\nI will always post the code of the content right after it, which will make you more easy to follow my poor English.<br \/>\n\\section{How to Write the Basic Information of Your Post}<br \/>\nJust as in LaTeX, you can use commands such as:\\emph{\\title}, \\emph{\\author}, \\emph{\\address}, \\emph{\\date}, \\emph{\\keywords} and the environment \\emph{abstract} to produce the basic information of your post. These command has the same meaning as in LaTeX, what&#8217;s more,<br \/>\n\\begin{itemize}<br \/>\n\\item you can use \\emph{\\}\\emph{today} in \\emph{\\date}<br \/>\n\\item you can use \\emph{\\emph} to emphasis some thing<br \/>\n\\item you can use \\emph{\\}\\emph{tableofcontents} to get the table of contents<br \/>\n\\item you can use \\emph{\\email} or \\emph{\\mailto} to set your mail, the first will be centered<br \/>\n\\end{itemize}<br \/>\n\\section{How to Write Section, Subsection and Subsubsection}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\section{How to Write Section, Subsection and Subsubsection}<\/pre>\n<p>Just like in Latex, isn&#8217;t it? Replace \\emph{\\section} with \\emph{\\subsection} and \\emph{\\subsubsection} if you want to write subsection and subsubsection, respectively. How about \\emph{\\subsubsubsection}? Sorry, there is no such command.<\/p>\n<p>Maybe you are still wandering: how do I get the list of contents by \\emph{\\}\\emph{tableofcontents} command, one key factor is that I added a link just before each section and subsection, by which you can refer to it. See the referring back to section (\\ref{sec:7.3}) for detail.<br \/>\n\\section{Itemize and Enumerate: How to List Stuffs}<br \/>\nAs you have already saw, we can list the element as<br \/>\n\\begin{itemize}<br \/>\n\\item Firstly<br \/>\n\\item Secondly<br \/>\n\\end{itemize}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{itemize}\n\\item Firstly\n\\item Secondly\n\\end{itemize}<\/pre>\n<p>What&#8217;s more you can nest them, for example<br \/>\n\\begin{itemize}<br \/>\n\\item Firstly<br \/>\n\\item Secondly<br \/>\n\\begin{itemize}<br \/>\n\\item The first item of Second<br \/>\n\\item The second item of Second<br \/>\n\\begin{itemize}<br \/>\n\\item The first item of the third item of second item<br \/>\n\\end{itemize}<br \/>\n\\end{itemize}<br \/>\n\\end{itemize}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{itemize}\n\\item Firstly\n\\item Secondly\n\\begin{itemize}\n\\item The first item of Second\n\\item The second item of Second\n\\begin{itemize}\n\\item The first item of the third item of second item\n\\end{itemize}\n\\end{itemize}\n\\end{itemize}\n<\/pre>\n<p>\\emph{Enumerate} works almost the same as \\emph{itemize}, except the style is different. For example replace \\emph{enumerate} in the above example with \\emph{enumerate}, then we get:<br \/>\n\\begin{enumerate}<br \/>\n\\item Firstly<br \/>\n\\item Secondly<br \/>\n\\begin{enumerate}<br \/>\n\\item The first item of Second<br \/>\n\\item The second item of Second<br \/>\n\\begin{enumerate}<br \/>\n\\item The first item of the third item of second item<br \/>\n\\end{enumerate}<br \/>\n\\end{enumerate}<br \/>\n\\end{enumerate}<br \/>\n\\section{The Color Scheme: How to Colorize You Content}<br \/>\nAs we have already showed that you can emphasis you content by \\emph{\\emph}, one other way is use \\emph{\\underline}. Besides, there is a more powerful scheme, now you emphasis some content with different colors, even for formulae.<br \/>\nFirstly, you must decide which class your content belonged to, the \\textcolor{green}{text} content or the \\textcolor{green}{mathematics} content, since these two classes are processed by different scheme, \\textcolor{green}{text} is by \\emph{latex2html} and \\textcolor{green}{mathematics} by \\emph{mathjax}.<br \/>\nJust as in Latex, the you can set a color for your formula by \\emph{\\color}\\emph{{color_name}}\\emph{{color_formula}}. For example<br \/>\n\\[<br \/>\n\\color{red}{a+b},\\quad\\color{blue}{a+b},\\quad\\color{green}{a+b}<br \/>\n\\]<br \/>\n\\[<br \/>\n\\frac{\\color{cyan}{a+b}}{c+d}, \\quad<br \/>\n\\frac{a}{\\color{magenta}{a+b}},\\quad<br \/>\n\\frac{a}{a+\\color{yellow}{b}}<br \/>\n\\]<\/p>\n<pre colla=\"+\" lang=\"latex\">\\[\n\\color{red}{a+b},\\quad\\color{blue}{a+b},\\quad\\color{green}{a+b}\n\\]\n\\[\n\\frac{\\color{cyan}{a+b}}{c+d}, \\quad\n\\frac{a}{\\color{magenta}{a+b}},\\quad\n\\frac{a}{a+\\color{yellow}{b}}\n\\]\n<\/pre>\n<p>On the other hand, if you want to give color for your \\textcolor{green}{text} content, then you should use<br \/>\n\\emph{\\textcolor{color_name}}\\emph{{color_contents}}, for example<br \/>\n\\textcolor{red}{red} and \\textcolor{blue}{blue} and \\textcolor{green}{green} and \\textcolor{cyan}{cyan} and \\textcolor{magenta}{magenta} and \\textcolor{yellow}{yellow}.<\/p>\n<pre colla=\"+\" lang=\"latex\">\\textcolor{red}{red} and\n\\textcolor{blue}{blue} and\n\\textcolor{green}{green} and\n\\textcolor{cyan}{cyan} and\n\\textcolor{magenta}{magenta} and\n\\textcolor{yellow}{yellow}<\/pre>\n<p>\\section{How to Write a Theorem}<br \/>\nThere are two group of environments, which process the content such as \\emph{Theorem}. One is used for a post, in which you mainly state something formally, just like you do in a research paper; The other is used for problem-discussion situation, in which you ask questions and hope for some examples and answers.<br \/>\nOf course the border is not so strict, for example the \\emph{examp} environment can used in both cases.<br \/>\nHere are the complete list of environments you can use (The example will be pop up at some time later), I take first few words of a environment to represent it, for example \\emph{thm} for \\emph{Theorem}:<br \/>\n\\begin{itemize}<br \/>\n\\item First group: \\emph{defn}(Definition), \\emph{lem}(Lemma), \\emph{prop}(Proposition), \\emph{thm}(Theorem), \\emph{cor}(Corollary), \\emph{rem}(Remark), \\emph{excs}(Exercise), \\emph{proof}(Proof)<br \/>\n\\item Second group: \\emph{prob}(Problem), \\emph{answer}(Answer)<br \/>\n\\item Mixed: \\emph{examp}(Example), \\emph{quote}(Quotation)<br \/>\n\\end{itemize}<br \/>\nI will go through the two group one by one, let&#8217;s begin with the first group.<br \/>\n\\subsection{Definition, Lemma, Proposition, Theorem, Corollary, Remark, Proof}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\subsection{Definition, Lemma, Proposition, Theorem, Corollary, Remark, Proof}<\/pre>\n<p>Firstly, you should keep in mind that: the distinguish between \\emph{command} and \\emph{environment} is<br \/>\n\\begin{quote}<br \/>\nA \\emph{command} begin with a \\emph{\\} and followed with the \\emph{name}, at last the content of command. It looks like <strong>\\<\/strong><strong>emph{text}<\/strong>; A \\emph{environment} must be wrapped by \\emph{begin} and \\emph{end}.<br \/>\n\\end{quote}<br \/>\n\\subsubsection{Basic Usage of Environments}<br \/>\nHere is an example of \\emph{definition} environment:<br \/>\n\\begin{defn}<br \/>\nSuppose that $(X,\\mathcal M)$ and $(Y,\\mathcal N)$ are measurable spaces, and $f:X\\to Y$ is a map. We call $f$ is \\emph{measurable} if for every $B\\in\\mathcal N$ the set $f^{-1}(B)$ is in $\\mathcal M$.<br \/>\n\\end{defn}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{defn}\nSuppose that $(X,\\mathcal M)$ and $(Y,\\mathcal N)$ are measurable spaces,\nand $f:X\\to Y$ is a map. We call $f$ is \\emph{measurable} if for every $B\\in\\mathcal N$\nthe set $f^{-1}(B)$ is in $\\mathcal M$.\n\\end{defn}<\/pre>\n<p>The other is similar, just replace \\emph{defn} with any one of the above environment:<br \/>\n\\begin{rem}<br \/>\nIf $Y$ is a topological space, and $\\mathcal N$ is the $\\sigma$-algebra of Borel sets, then $f$ is measurable if and only if the following condition satisfied:<br \/>\n\\begin{itemize}<br \/>\n\\item For every open set $V$ in $Y$, the inverse image $f^{-1}(V)$ is measurable.<br \/>\n\\end{itemize}<br \/>\n\\end{rem}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{rem}\nIf $Y$ is a topological space, and $\\mathcal N$ is the $\\sigma$-algebra of Borel sets,\nthen $f$ is measurable if and only if the following condition satisfied:\n\\begin{itemize}\n\\item For every open set $V$ in $Y$, the inverse image $f^{-1}(V)$ is measurable.\n\\end{itemize}\n\\end{rem}<\/pre>\n<p>\\subsubsection{Assign a Name for Your Theorem}<br \/>\nYou can even assign a name to these environment, just as you did in latex, use \\emph{[text]} just behind the environment, for example:<br \/>\n\\begin{lem}[fundamental lemma of integration]<br \/>\nLet $\\set{f_n}$ be a Cauchy sequence of step mappings. Then there exists a subsequence which converges pointwise almost everywhere, and satisfies the additional property: given $\\eps$ there exists a set $Z$ of measure $&lt; \\eps$ such that this subsequence converges absolutely and uniformly outside $Z$.<br \/>\n\\end{lem}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{lem}[fundamental lemma of integration]\nLet $\\set{f_n}$ be a Cauchy sequence of step mappings. Then there exists a subsequence\nwhich converges pointwise almost everywhere, and satisfies the additional property:\ngiven $\\eps$ there exists a set $Z$ of measure $&lt; \\eps$ such that this subsequence\nconverges absolutely and uniformly outside $Z$.\n\\end{lem}<\/pre>\n<p>\\subsubsection{The Proof Environment}<br \/>\nThe following are the \\emph{proof} environment, and some more examples, if you are impatient to other contents, then just skip this subsection by click \\ref{sec:6.2}.<br \/>\n\\begin{proof}<br \/>\nFor each integer $k$ there exists $N_k$ such that if $m,n\\geq N_k$, then<br \/>\n\\[<br \/>\n\\|f_m-f_n\\|_1&lt; \\frac{1}{2^{2k}}.<br \/>\n\\]<br \/>\nWe let our subsequence be $g_k=f_{N_k}$, taking the $N_k$ inductively to be strictly increasing. Then we have for all $m,n$:<br \/>\n\\[<br \/>\n\\|g_m-g_n\\|_1 \\]<br \/>\nWe shall show that the series<br \/>\n\\[<br \/>\ng_1(x)+\\sum_{k=1}^\\infty\\left(g_{k+1}(x)-g_k(x)\\right)<br \/>\n\\]<br \/>\nconverges absolutely for almost all $x$ to an element of $E$, and in fact we shall prove that this convergence is uniform except on a set of arbitrarily small measure.<br \/>\nLet $Y_n$ be the set of $x\\in X$ such that<br \/>\n\\[<br \/>\n|g_{n+1}(x)-g_n(x)|\\geq\\frac{1}{2^n}.<br \/>\n\\]<br \/>\nSince $g_n$ and $g_{n+1}$ are step mappings, it follows that $Y_n$ has finite measure. On $Y_n$ we have the inequality<br \/>\n\\[<br \/>\n\\frac{1}{2^n}\\leq|g_{n+1}-g_n|<br \/>\n\\]<br \/>\nwhence<br \/>\n\\[<br \/>\n\\frac{1}{2^n}\\mu(Y)=\\int_{Y_n}\\frac{1}{2^n}\\leq\\int_X|g_{n+1}-g_{n}|\\leq\\frac{1}{2^{2n}}.<br \/>\n\\]<br \/>\nHence<br \/>\n\\[<br \/>\n\\mu(Y_n)\\leq\\frac{1}{2^n}.<br \/>\n\\]<br \/>\nLet<br \/>\n\\[<br \/>\nZ_n=Y_n\\cup Y_{n+1}\\cup\\cdots.<br \/>\n\\]<br \/>\nThen<br \/>\n\\[<br \/>\n\\mu(Z_n)\\leq \\frac{1}{2^{n-1}}.<br \/>\n\\]<br \/>\nIf $x\\not\\in Z_n$, then for $k\\geq n$ we have<br \/>\n\\[<br \/>\n|g_{k+1}(x)-g_k(x)| \\]<br \/>\nand from this we conclude that our series<br \/>\n\\[<br \/>\n\\sum_{k=n}^\\infty\\left(g_{k+1}(x)-g_{k}(x)\\right)<br \/>\n\\]<br \/>\nis absolutely and uniformly convergent, for $x\\not\\in Z_n$. This proves the statement concerning the uniform convergence. If we let $Z$ be the intersection of all $Z_n$, then $Z$ has measure $0$, and if $x\\not\\in Z$, then $x\\not\\in Z_n$ for some $n$, whence our series converges for this $x$. This proves the lemma.<br \/>\n\\end{proof}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{proof}\nFor each integer $k$ there exists $N_k$ such that if $m,n\\geq N_k$, then\n\\[\n\\|f_m-f_n\\|_1&lt; \\frac{1}{2^{2k}}.\n\\]\nWe let our subsequence be $g_k=f_{N_k}$, taking the $N_k$ inductively to be strictly increasing. Then we have for all $m,n$:\n\\[\n\\|g_m-g_n\\|_1 \\]\nWe shall show that the series\n\\[\ng_1(x)+\\sum_{k=1}^\\infty\\left(g_{k+1}(x)-g_k(x)\\right)\n\\]\nconverges absolutely for almost all $x$ to an element of $E$, and in fact we shall prove that this convergence is uniform except on a set of arbitrarily small measure.\nLet $Y_n$ be the set of $x\\in X$ such that\n\\[\n|g_{n+1}(x)-g_n(x)|\\geq\\frac{1}{2^n}.\n\\]\nSince $g_n$ and $g_{n+1}$ are step mappings, it follows that $Y_n$ has finite measure. On $Y_n$ we have the inequality\n\\[\n\\frac{1}{2^n}\\leq|g_{n+1}-g_n|\n\\]\nwhence\n\\[\n\\frac{1}{2^n}\\mu(Y)=\\int_{Y_n}\\frac{1}{2^n}\\leq\\int_X|g_{n+1}-g_{n}|\\leq\\frac{1}{2^{2n}}.\n\\]\nHence\n\\[\n\\mu(Y_n)\\leq\\frac{1}{2^n}.\n\\]\nLet\n\\[\nZ_n=Y_n\\cup Y_{n+1}\\cup\\cdots.\n\\]\nThen\n\\[\n\\mu(Z_n)\\leq \\frac{1}{2^{n-1}}.\n\\]\nIf $x\\not\\in Z_n$, then for $k\\geq n$ we have\n\\[\n|g_{k+1}(x)-g_k(x)| \\]\nand from this we conclude that our series\n\\[\n\\sum_{k=n}^\\infty\\left(g_{k+1}(x)-g_{k}(x)\\right)\n\\]\nis absolutely and uniformly convergent, for $x\\not\\in Z_n$. This proves the statement concerning the uniform convergence. If we let $Z$ be the intersection of all $Z_n$, then $Z$ has measure $0$, and if $x\\not\\in Z$, then $x\\not\\in Z_n$ for some $n$, whence our series converges for this $x$. This proves the lemma.\n\\end{proof}\n<\/pre>\n<p>\\subsubsection{More Examples of Environments}<br \/>\n\\begin{thm}<br \/>\nLet $f_n$ be a Cauchy sequence in $\\mathcal L^1$ which is $L^1$-convergent to an element $f$ in $\\mathcal L^1$. Then there exists a subsequence which converges to $f$ almost everywhere, and also such that given $\\eps$, there exists a set $Z$ of measure $&lt; \\eps$ such that the convergence is uniform on the complement of $Z$.<br \/>\n\\end{thm}<\/p>\n<pre lang=\"latex\">\\begin{thm}\nLet $f_n$ be a Cauchy sequence in $\\mathcal L^1$ which is $L^1$-convergent to an element $f$ in $\\mathcal L^1$. Then there exists a subsequence which converges to $f$ almost everywhere, and also such that given $\\eps$, there exists a set $Z$ of measure $&lt; \\eps$ such that the convergence is uniform on the complement of $Z$.\n\\end{thm}<\/pre>\n<p>\\begin{cor}<br \/>\nAn element $f\\in\\mathcal L^1$ has seminorm $\\|f\\|_1=\\int_X|f|\\rd\\mu=0$ if and only if $f$ is equal to $0$ almost everywhere.<br \/>\n\\end{cor}<\/p>\n<pre lang=\"latex\">\\begin{cor}\nAn element $f\\in\\mathcal L^1$ has seminorm $\\|f\\|_1=\\int_X|f|\\rd\\mu=0$ if and only if $f$ is equal to $0$ almost everywhere.\n\\end{cor}<\/pre>\n<p>\\begin{prop}[Monotone Convergence Theorem]<br \/>\nLet $\\set{f_n}$ be an increasing (resp. decreasing) sequence of real valued functions in $\\mathcal L^1$ such that the integrals<br \/>\n\\[<br \/>\n\\int_X f_n\\rd\\mu<br \/>\n\\]<br \/>\nare bounded. Then $\\set{f_n}$ is a Cauchy sequence, and is both $\\mathcal L^1$ and almost everywhere convergent to some function $f\\in\\mathcal L^1$.<br \/>\n\\end{prop}<\/p>\n<pre lang=\"latex\">\\begin{cor}\nAn element $f\\in\\mathcal L^1$ has seminorm $\\|f\\|_1=\\int_X|f|\\rd\\mu=0$ if and only if $f$ is equal to $0$ almost everywhere.\n\\end{cor}<\/pre>\n<p>\\begin{prop}[Fatou&#8217;s Lemma]<br \/>\nLet $\\set{f_n}$ be a sequence of real valued non-negative functions in $\\mathcal L^1$. Assume that<br \/>\n\\[<br \/>\n\\liminf\\|f_n\\|_1<br \/>\n\\]<br \/>\nis exists (so is a real number $\\geq0$). Then $\\liminf f_n(x)$ exists for almost all $x$, the function $\\liminf f_n$ is in $\\mathcal L^1$, and we have<br \/>\n\\[<br \/>\n\\int_X\\liminf f_n\\rd \\mu\\leq\\liminf\\int_X f_n\\rd\\mu=\\liminf\\|f_n\\|_1.<br \/>\n\\]<br \/>\n\\end{prop}<\/p>\n<pre lang=\"latex\">\\begin{prop}[Fatou's Lemma]\nLet $\\set{f_n}$ be a sequence of real valued non-negative functions in $\\mathcal L^1$. Assume that\n\\[\n\\liminf\\|f_n\\|_1\n\\]\nis exists (so is a real number $\\geq0$). Then $\\liminf f_n(x)$ exists for almost all $x$, the function $\\liminf f_n$ is in $\\mathcal L^1$, and we have\n\\[\n\\int_X\\liminf f_n\\rd \\mu\\leq\\liminf\\int_X f_n\\rd\\mu=\\liminf\\|f_n\\|_1.\n\\]\n\\end{prop}<\/pre>\n<p>\\subsection{The Problem, Answer Environments}<br \/>\nThe second group of environments are provided for discussion, after all, this is a discussion platform. They are: \\emph{prob} for Problem, \\emph{examp} for Example, and \\emph{answer} for Answer.<br \/>\nIt almost works the same as the first group, for example<br \/>\n\\begin{prob}[Egoroff&#8217;s theorem]<br \/>\nAssume that $\\mu$ is $\\sigma$-finite. Let $f:X\\to E$ be a map and assume that $f$ is the pointwise limit of a sequence of simple maps $\\set{\\varphi_n}$. Given $\\eps$, show that there exists a set $Z$ with $\\mu(Z)&lt; \\eps$ such that the convergence of $\\set{\\varphi_n}$ is uniform on the complement of $Z$.<br \/>\n\\end{prob}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{prob}[Egoroff's theorem]\nAssume that $\\mu$ is $\\sigma$-finite. Let $f:X\\to E$ be a map and assume that $f$ is the pointwise limit of a sequence of simple maps $\\set{\\varphi_n}$. Given $\\eps$, show that there exists a set $Z$ with $\\mu(Z)&lt; \\eps$ such that the convergence of $\\set{\\varphi_n}$ is uniform on the complement of $Z$.\n\\end{prob}<\/pre>\n<p>But, the differences between them is that, the \\emph{answer} is numbered with \\emph{prob} (the \\emph{examp}, \\emph{excs}, \\emph{rem} will numbered independently), to see this, for example:<br \/>\n\\begin{answer}<br \/>\nAssume first that $\\mu(X)$ is finite. Let $A_k$ be the set where $|f|\\geq k$. The intersection of all $A_k$ is empty so their measures tend to $0$. Excluding a set of small measure, you can assume that $f$ is bounded, in which case $f$ is in $\\mathcal L^1(\\mu)$ and you can use the fundamental lemma of integration.<br \/>\n\\end{answer}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{answer}\nAssume first that $\\mu(X)$ is finite. Let $A_k$ be the set where $|f|\\geq k$. The intersection of all $A_k$ is empty so their measures tend to $0$. Excluding a set of small measure, you can assume that $f$ is bounded, in which case $f$ is in $\\mathcal L^1(\\mu)$ and you can use the fundamental lemma of integration.\n\\end{answer}<\/pre>\n<p>\\begin{answer}<br \/>\nThis is another answer for the problem.<br \/>\n\\end{answer}<br \/>\nYou should note that the number of answer is reset to 1 by \\emph{prob}, of course, more sensible. For example:<br \/>\n\\begin{prob}<br \/>\nWhy we should firstly process the positive measurable functions, then the real measurable functions and at last the complex measurable functions for the integral of measurable functions?<br \/>\n\\end{prob}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{prob}\nWhy we should firstly process the positive measurable functions, then the real measurable functions and at last the complex measurable functions for the integral of measurable functions?\n\\end{prob}<\/pre>\n<p>There are the answers for this problem:<br \/>\n\\begin{answer}<br \/>\nIn fact, you can define the integral of complex function directly.<br \/>\n\\end{answer}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{answer}\nIn fact, you can define the integral of complex function directly.\n\\end{answer}<\/pre>\n<p>\\begin{answer}<br \/>\nThere is another more instructive answer&#8230;<br \/>\n\\end{answer}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{answer}\nThere is another instructive answer...\n\\end{answer}<\/pre>\n<p>\\subsection{The Exercise Environment}<br \/>\nMaybe, at somewhere, you want the reader consider about something, then you can use \\emph{excs} environment for Exercise. <em>Please keep in mind that it will have independent numbering, just as \\emph{prob}, but will \\emph{not reset} the number of answer<\/em>. Here is an example:<br \/>\n\\begin{excs}<br \/>\nSuppose $(X,\\mu)$ is a measure space, and that $f$ is measurable, then $\\int_X f\\rd \\mu=0$ if and only if $f\\equiv0$ almost everywhere.<br \/>\n\\end{excs}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{excs}\nSuppose $(X,\\mu)$ is a measure space, and that $f$ is measurable, then $\\int_X f\\rd \\mu=0$ if and only if $f\\equiv0$ almost everywhere.\n\\end{excs}<\/pre>\n<p>\\subsection{The Quote Environment}<br \/>\nSometimes, there are some words or comments on the content, it is like a remark, but it is not so formal. And, if you are write a lecture notes, these words may be the lecturer said before or after an important thing, such as theorems. I have defined a new environment \\emph{quote} to deal with these stuff. For example:<br \/>\nBefore the theorem<br \/>\n\\begin{thm}<br \/>\nLet $\\Omega\\subset\\R^n$ and $u:\\Omega\\to\\R$, then<br \/>\n\\begin{enumerate}<br \/>\n\\item If $u\\in C^2(\\Omega)$ is harmonic in $\\Omega$, then $u$ satisfies MVP;<br \/>\n\\item If $u\\in C(\\Omega)$ satisfies MVP, then $u$ is smooth and harmonic.<br \/>\n\\end{enumerate}<br \/>\n\\end{thm}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{thm}\n  Let $\\Omega\\subset\\R^n$ and $u:\\Omega\\to\\R$, then\n  \\begin{enumerate}\n    \\item If $u\\in C^2(\\Omega)$ is harmonic in $\\Omega$, then $u$ satisfies MVP;\n    \\item If $u\\in C(\\Omega)$ satisfies MVP, then $u$ is smooth and harmonic.\n  \\end{enumerate}\n\\end{thm}<\/pre>\n<p>we want to add a comment on it, then you can use<br \/>\n\\begin{quote}<br \/>\nA function satisfying mean-value properties is only required to be continuous. However, a harmonic function is required to be $C^2$. Thus, the equivalence of this two kind of functions will be significant.<br \/>\n\\end{quote}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{quote}\nA function satisfying mean-value properties is only required to be continuous. However, a harmonic function is required to be $C^2$. Thus, the equivalence of this two kind of functions will be significant.\n\\end{quote}<\/pre>\n<p>\\section{Auto Numbering and Referring Back}<br \/>\n\\textcolor{red}{PLEASE\u3000NOTE THAT: since1.2.3, the auto number scheme is done by MathJax, not my plugin any more, so please visit mathjax for how to use the auto-numbering scheme)}<br \/>\n\\subsection{Auto Numbering and Referring Back to Equations}<br \/>\n\\subsubsection{Basic Usage of Mathematical Environments}<br \/>\nAll the \\emph{mathematical} environments: <strong>equation<\/strong>, <strong>align<\/strong>, <strong>multline<\/strong>, <strong>gather<\/strong> will auto-numbering. For example<br \/>\n\\begin{equation}\\begin{cases}<br \/>\n3=2x+y\\\\<br \/>\n3=y+2x\\end{cases}<br \/>\n\\end{equation}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{equation}\\begin{cases}\n3=2x+y\\\\\n3=y+2x\\end{cases}\n\\end{equation}<\/pre>\n<p>An example of \\emph{multline}, which will make the last line flush right:<br \/>\n\\begin{multline}\\label{eq:2}<br \/>\n\\int_a^b \\biggl\\{ \\int_a^b [ f(x)^2 g(y)^2 + f(y)^2 g(x)^2 ]<br \/>\n-2f(x) g(x) f(y) g(y) \\,dx \\biggr\\} \\,dy \\\\<br \/>\n=\\int_a^b \\biggl\\{ g(y)^2 \\int_a^b f^2 + f(y)^2<br \/>\n\\int_a^b g^2 &#8211; 2f(y) g(y) \\int_a^b fg \\biggr\\} \\,dy<br \/>\n\\end{multline}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{multline}\\label{eq:2}\n\\int_a^b \\biggl\\{ \\int_a^b [ f(x)^2 g(y)^2 + f(y)^2 g(x)^2 ]\n-2f(x) g(x) f(y) g(y) \\,dx \\biggr\\} \\,dy \\\\\n=\\int_a^b \\biggl\\{ g(y)^2 \\int_a^b f^2 + f(y)^2\n\\int_a^b g^2 - 2f(y) g(y) \\int_a^b fg \\biggr\\} \\,dy\n\\end{multline}<\/pre>\n<p>The next example will show how to numbered the equation at a given line:<br \/>\n\\begin{gather}<br \/>\n\\begin{split}<br \/>\n\\varphi(x,z)<br \/>\n&amp;= z \u2013 \\gamma_{10} x \u2013 \\sum_{m+n\\ge2} \\gamma_{mn} x^m z^n\\\\<br \/>\n&amp;= z \u2013 M r^{-1} x \u2013 \\sum_{m+n\\ge2} M r^{-(m+n)} x^m z^n<br \/>\n\\end{split}\\tag{4}\\\\<br \/>\n\\begin{split}<br \/>\n\\zeta^0 &amp;= (\\xi^0)^2, \\\\<br \/>\n\\zeta^1 &amp;= \\xi^0 \\xi^1<br \/>\n\\end{split}\\notag<br \/>\n\\end{gather}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{gather}\n\\begin{gather}\n\\begin{split}\n\\varphi(x,z) \n&amp;= z \u2013 \\gamma_{10} x \u2013 \\sum_{m+n\\ge2} \\gamma_{mn} x^m z^n\\\\ \n&amp;= z \u2013 M r^{-1} x \u2013 \\sum_{m+n\\ge2} M r^{-(m+n)} x^m z^n \n\\end{split}\\tag{4}\\\\ \n\\begin{split} \n\\zeta^0 &amp;= (\\xi^0)^2, \\\\ \n\\zeta^1 &amp;= \\xi^0 \\xi^1 \n\\end{split}\\notag\n\\end{gather}<\/pre>\n<p>\\subsubsection{Auto Numbering Scheme of Equations}<br \/>\nI hope you have already noticed that the above equations are numbered automatically, in fact, this is my first goal to write a plugin to process the latex code. Mathjax process mathematical perfectly, the only non-advantage is that it can&#8217;t automatically add number for equations. When I got a way to add number for the equations automatically, I found that I can go a litter far<br \/>\n\\begin{enumerate}<br \/>\n\\item automatically numbering theorems, which can be realize by set \\emph{CSS}&#8217;s \\emph{before} element with a \\emph{counter}, but it may not work for IE6;<br \/>\n\\item automatically numbering sections, and which can produce a table of contents, as you have already see.<br \/>\n\\end{enumerate}<br \/>\nThen, when did the equation should be added number automatically?<br \/>\nHere is the rule:<br \/>\n\\begin{enumerate}<br \/>\n\\item If you use either one of these environments: \\emph{equation,align,multline,gather};<br \/>\n\\item If you do use these environments, then \\emph{latex2html} will search \\emph{tag,notag} sign inside these environments;<br \/>\n\\item If it find a \\emph{tag}, then it will reset the number of equation (\\emph{$eqn}); one reason is that, \\emph{\\tag{eqn_num}} will set the present equation with number \\emph{eqn_num}, another more important reason is that you can set the equation number as \\emph{2.a, 2.b, 3.a.b, 3.a.c} and so on.<br \/>\n\\item If it find \\emph{notag} in the equation body, then it will make this equation without number<br \/>\n\\item If neither \\emph{tag} nor \\emph{notag} have found, then it will assign a new number to the equation, i.e., \\emph{$eqn};<br \/>\n\\end{enumerate}<br \/>\n\\subsubsection{How to Numbered Equations by 3.a and 3.b}<br \/>\nHere is an example with varied number:<br \/>\n\\begin{align}<br \/>\nx^2+y^2&amp;=z^2,\\quad{x,y,z\\in\\mathbb{Z}}\\tag{5.a}\\\\<br \/>\nx^3+y^3&amp;=z^3,\\quad{x,y,z\\in\\mathbb{Z}}\\tag{5.b}<br \/>\n\\end{align}<br \/>\n\\begin{equation}<br \/>\nx^4+y^4=z^4,\\quad{x,y,z\\in\\mathbb{Z}}\\tag{7.a.b}<br \/>\n\\end{equation}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{align}\nx^2+y^2&amp;=z^2,\\quad{x,y,z\\in\\mathbb{Z}}\\tag{5.a}\\\\\nx^3+y^3&amp;=z^3,\\quad{x,y,z\\in\\mathbb{Z}}\\tag{5.b}\n\\end{align}\n\\begin{equation}\nx^4+y^4=z^4,\\quad{x,y,z\\in\\mathbb{Z}}\\tag{7.a.b}\n\\end{equation}<\/pre>\n<p>I want to say a liter words about this scheme, i.e., numbering with \\emph{num.lower-case-alpha}:<br \/>\n\\begin{itemize}<br \/>\n\\item first, the style of tag must be number plus lower-case-alpha, with dot split them, and there may be more than one lower-case-alpha, but the first one must be a number, of course may be more than one digit;<br \/>\n\\item these scheme is designed for the group of equations are similar, thus their numbering is almost the same<br \/>\n\\item in order to refer to these equations, you should use something like \\emph{\\eqref}\\emph{{eq:5.a}} or \\emph{\\eqref}\\emph{{eq:5.b}}, see \\ref{sec:7.1.5} for more details.<br \/>\n\\item the number of the next equation will be \\emph{num}+1<br \/>\n\\end{itemize}<br \/>\nFor example, if you write another equation, which you would like to numbered automatically, then this equation will be numbered as \\emph{(8)} in the present situation, since we already used \\emph{7} in \\emph{7.a.b}. For example,<br \/>\n\\begin{gather}<br \/>\n\\int_a^b \\biggl\\{ \\int_a^b [ f(x)^2 g(y)^2 + f(y)^2 g(x)^2 ]<br \/>\n-2f(x) g(x) f(y) g(y) \\,dx \\biggr\\} \\,dy \\\\<br \/>\n=\\int_a^b \\biggl\\{ g(y)^2 \\int_a^b f^2 + f(y)^2<br \/>\n\\int_a^b g^2 &#8211; 2f(y) g(y) \\int_a^b fg \\biggr\\} \\,dy<br \/>\n\\end{gather}<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{gather}\n\\int_a^b \\biggl\\{ \\int_a^b [ f(x)^2 g(y)^2 + f(y)^2 g(x)^2 ]\n-2f(x) g(x) f(y) g(y) \\,dx \\biggr\\} \\,dy \\\\\n=\\int_a^b \\biggl\\{ g(y)^2 \\int_a^b f^2 + f(y)^2\n\\int_a^b g^2 - 2f(y) g(y) \\int_a^b fg \\biggr\\} \\,dy\n\\end{gather}<\/pre>\n<p>\\subsubsection{Skip Auto Numbering of Equations}<br \/>\nAny one of the following thing will make the auto-numbering scheme false:<br \/>\n\\begin{itemize}<br \/>\n\\item use the stared version of environments, for example you use \\emph{equation*} instead of \\emph{equation}<br \/>\n\\item use the \\emph{\\tag{your_number}} that will make the equation numbered by \\emph{your_number} given in \\emph{\\tag}<br \/>\n\\item use \\emph{\\notag} that will make the equation \\emph{without number}, but there should be no manually set \\emph{\\tag}<br \/>\n\\item (\\textcolor{red}{This drawback has already fixed by removing the \\emph{\\}\\emph{label{*}} before processing the equation}) <del datetime=\"2013-10-05T00:27:10+00:00\">Another not-so-perfect thing is that you should not write a \\emph{\\label} or \\emph{\\notag} just behind the \\emph{begin} part<\/del>. (\\textcolor{red}{Since the label now is process by mathjax, the following is not appear anymore!})For example, if you write something like<br \/>\n\\begin{equation}\\label{eq:3}<br \/>\na+b=c\\quad \\text{it not numbered, since you have set a }\\textbf{\\label}\\text{ for it}<br \/>\n\\end{equation}<br \/>\nThe code of above equation is:<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{equation}\\label{eq:3}\na+b=c\\quad \\text{it not numbered, since you have set a }\\textbf{\\label}\\text{ for it}\n\\end{equation}<\/pre>\n<p>Considering this drawback, I try to fix it by warping the automatic added \\emph{lable} and \\emph{\\notag} with an \\emph{{}} to distinguish these are added manually. In other words, this will make the following equation auto-number:<\/p>\n<pre colla=\"+\" lang=\"latex\">\\begin{equation}{\\label{eq:3}}\na+b=c\\quad \\text{it not numbered, since you have set a }\\textbf{\\label}\\text{ for it}\n\\end{equation}<\/pre>\n<p>\\end{itemize}<br \/>\n\\subsubsection{How to Refer back to Equation Number}<br \/>\nYou can refer back to a \\emph{numbered equation} by \\emph{\\eqref}, please note that the \\emph{\\ref} is used for another stuff, so please use \\emph{\\eqref} for equations, and which will add \\emph{()} automatically.<br \/>\nFor example:<br \/>\ncan you see the difference between \\eqref{eq:2} and \\eqref{eq:8}?<\/p>\n<pre colla=\"+\" lang=\"latex\">can you see the difference between \\eqref{eq:2} and \\eqref{eq:8}?<\/pre>\n<p>Please note that the difference is that \\eqref{eq:8} is \\emph{centered} for all lines.<br \/>\nThe important thing in using \\emph{\\eqref} is that it must looks like \\emph{\\eqref{eq:number}}, here the \\emph{eq:} inside {} is fixed, and the \\emph{number} is the number for your equation, which either auto-added by \\emph{latex2html} or set manually by you.<br \/>\nIf you want refer back to the equation with number \\emph{5.a} or \\emph{5.b}, it should be exactly as \\eqref{eq:5.a} or \\eqref{eq:5.b}, and no equation has associated with \\eqref{eq:5}. Please have a check that which one of the above link works?<\/p>\n<pre colla=\"+\" lang=\"latex\">If you want refer back to the equation with number \\emph{5.a} or \\emph{5.b}, it should be exactly as\n\\eqref{eq:5.a} or \\eqref{eq:5.b}, and no equation has associated with \\eqref{eq:5}. Please have\na check that which one of the above link works?<\/pre>\n<p>\\subsubsection{My Suggestion on &#8220;How to Write Equations&#8221;}<br \/>\n\\begin{enumerate}<br \/>\n\\item if you use \\emph{&gt;} or \\emph{&lt; } for \\emph{greater} and \\emph{lesser} in math, please add a blank-space before \\emph{&gt;} and a blank-space after \\emph{&lt; }. Or you will make the HTML translation program confused, since \\emph{} are standard tags for HTML language(code).<br \/>\n\\item use\\emph{$$} for inline math<br \/>\n\\item use\\emph{\\[}\\emph{\\]} for oneline unnumbered display math<br \/>\n\\item use star version for multiline unnumbered display math, for example, use \\emph{gather*} environment for centered multiline equations<br \/>\n\\item use \\emph{equation} environment for oneline numbered display math<br \/>\n\\item use \\emph{align} environment for multiline numered display math, if you want make them aligned at some position( use &amp; to set the point of align)<br \/>\n\\end{enumerate}<br \/>\n\\subsection{Auto Numbering and Referring Back to Environments}<br \/>\n\\subsubsection{Auto Numbering of Environments}<br \/>\nAll the environments except \\emph{proof} are auto numbered by \\emph{latex2html}, and the \\emph{rem}, \\emph{prob}, \\emph{excs} are numbered independently, what&#8217;s more, \\emph{answer}&#8217;s number will be reset by \\emph{prob}. The other environment will numbered continuously in one post (on one page, which means, if you use the &lt;!&#8211;nextpage&#8211;&gt; to have another page, then the number will all over begin from 1, if you consider this as an bug, sorry, I can&#8217;t fix it.)<br \/>\n\\subsubsection{Referring Back to Environments}<br \/>\nYou can refer to the \\emph{Theorem}, \\emph{Lemma}, \\emph{Corollary}, \\emph{Definition}, \\emph{Proposition}, \\emph{Remark}, \\emph{Problem}, \\emph{Exercise}, and \\emph{Answer} environments by \\emph{\\ref{env_name:env_num}}. For example:<br \/>\nFrom \\ref{defn:1} we know that&#8230;<br \/>\nFrom \\ref{prop:4} we know that&#8230;<br \/>\nFrom \\ref{answer:2.1} we know that&#8230;<\/p>\n<pre colla=\"+\" lang=\"latex\">From \\ref{defn:1}  we know that...\nFrom \\ref{prop:4} we know that...\nFrom \\ref{answer:2.1} we know that...<\/pre>\n<p>Just like the referring back to the equations, when you use \\emph{\\ref{env_name:env_num}<strong>}<\/strong> to refer to the exist environments, you should note that<br \/>\n\\begin{itemize}<br \/>\n\\item the environments, such as \\emph{thm}, are auto numbered by \\emph{latex2html};<br \/>\n\\item \\emph{env_name} is the name of environment, such as \\emph{thm}, \\emph{answer} and so on.<br \/>\n\\item \\emph{env_num} is the number of the environment, you must assure that it is exists, which means that should matched with your environment. For example, if you write something such as \\emph{\\ref}\\emph{{prop:6}} that will not work, since there isn&#8217;t a \\emph{Proposition} numbered with \\emph{6}<br \/>\n\\item Referring to the \\emph{answer} is a litter different, the \\emph{env_num} looks like \\emph{2.1}, in other words, it should be exactly as the number in the post.<br \/>\n\\item The style of \\emph{\\ref} must looks like \\emph{\\ref}\\emph{{lem:2}}, which means, the \\emph{:} is important.<br \/>\n\\end{itemize}<br \/>\n\\subsection{Referring Back to Section}<br \/>\nYou can use \\emph{\\ref}\\emph{{sec:1}} to refer back to \\ref{sec:1}, and \\emph{\\ref}\\emph{{sec:6.1}} to refer back to Subsection 1 of Section 6, which will looks like \\ref{sec:6.1}, and \\emph{\\ref}\\emph{{sec:7.1.3}} to refer back to Subsubsection 3 of Subsection 1 of Section 7, which will looks like \\ref{sec:7.1.3}.<\/p>\n<pre colla=\"+\" lang=\"latex\">You can use \\emph{\\ref}\\emph{{sec:1}} to refer back to \\ref{sec:1}, and \\emph{\\ref}\\emph{{sec:6.1}} to refer back to Subsection 1 of Section 6, which will looks like \\ref{sec:6.1}, and \\emph{\\ref}\\emph{{sec:7.1.3}} to refer back to Subsubsection 3 of Subsection 1 of Section 7, which will looks like \\ref{sec:7.1.3}.<\/pre>\n<p>\\section{To-be Stuff}<br \/>\nMaybe in what follows I will try to make the \\emph{cite} of \\emph{Bibitem} available, but that&#8217;s just maybe, since my programming with \\emph{php} is badly poor, I hope somebody will make these thing become true.<br \/>\n\\section{The Pre-definition in Your TeX File}<br \/>\nIn order to make publish a post from your TeX code become more easy, I suggest add the following code in your Tex document:<\/p>\n<pre colla=\"+\" lang=\"latex\">%new theorem\n\\newtheorem{defn}{Definiton}\n\\newtheorem{prop}[defn]{Proposition}\n\\newtheorem{lem}[defn]{Lemma}\n\\newtheorem{thm}[defn]{Theorem}\n\\newtheorem{cor}[defn]{Corollary}\n\\newtheorem{rem}{Remark}\n\n\\newtheorem{prob}{Problem}\n\\newtheorem{excs}{Exercise}\n\\newtheorem{answer}{Answer}[prob]\n\n%newcommand\n\\newcommand{\\eps}{\\varepsilon}\n\\newcommand{\\R}{\\bm{R}}\n\\newcommand{\\rd}{\\operatorname{d}}\n\\newcommand{\\set}[1]{\\left\\{#1\\right\\}}\n\n%new environments\n%the quote\n\\renewenvironment{quote}{%\n\\par\\vspace{1.5\\baselineskip}%\n\\hspace{\\stretch{0.2}}\\minipage[c]{.9\\textwidth}\\itshape}{%\n\\endminipage\\hspace{\\stretch{1}}\\vspace{1.5\\baselineskip}\\par}\n<\/pre>\n<p>You can added your own definition of \\emph{symbols} to the post by \\emph{$}\\emph{your_definition_of_symbols}\\emph{$}, and place it at the beginning of the post. For example, if you add \\emph{$}<strong>\\newcommand{\\curl}{\\mathrm{curl}}<\/strong>\\emph{$} at the beginning of a post content, then you can use \\emph{\\curl} in formula to get the upward form of curl(\u65cb\u5ea6).<br \/>\n\\section{Last Words and Feed Back}<br \/>\nThis document contains the usage of the plugin \\emph{latex2html}, and if you find any errors, or have any suggestions even bugs of the plugin, you can leave a word here, or sent a mail to me: \\mailto{van141.abel@gmail.com}.<\/p>\n<p>It takes me about one week to write the plugin, I&#8217;m too tired to feel glad when I finally finished it. I don&#8217;t know whether it will help you a litter to post mathematics with latex language or not, but if it do have any, I will fell much better.<br \/>\n\\subsection{How to Jump Between Links}<br \/>\nIf you have just click on a link, then you can go back where you were just by \\emph{Alt+\u2190}<\/p>\n<div style=\"text-align: center;\"><span style=\"color: #99cc00; font-size: 1.5em;\">Now what? Just enjoy the \\emph{latex2html} plugin!!<\/span><\/div>\n<p>\\section{How to Get it?}<br \/>\n<del datetime=\"2013-01-24T00:20:59+00:00\">You can download it here by right-click the following download link and save it as&#8230;, then you can install it as the usual plugins.<br \/>\n<a href=\"http:\/\/wamath-wordpress.stor.sinaapp.com\/uploads\/2012\/01\/latex2html.zip\">Downlad LaTeX2HTML<\/a><\/del><br \/>\nTo get it, visit the plugin in wordpress: <a href=\"http:\/\/wordpress.org\/extend\/plugins\/latex2html\/\" target=\"_blank\">http:\/\/wordpress.org\/extend\/plugins\/latex2html\/<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>\\title{Introduction to LaTeX2HTML Plugin &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"more-link\" href=\"https:\/\/lttt.vanabel.cn\/?p=1759\"> <span class=\"screen-reader-text\">Introduction of LaTeX2HTML Plugin<\/span> \u9605\u8bfb\u66f4\u591a &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[535,589],"class_list":["post-1759","post","type-post","status-publish","format-standard","hentry","category-admin","tag-latex2html","tag-plugin"],"_links":{"self":[{"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=\/wp\/v2\/posts\/1759","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1759"}],"version-history":[{"count":0,"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=\/wp\/v2\/posts\/1759\/revisions"}],"wp:attachment":[{"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1759"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1759"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/lttt.vanabel.cn\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1759"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}